 # Obfuscation Challenge #1 (Basic -> Advanced)

## obfuscate

ob·fus·cate \ˈäb-fə-ˌskāt; äb-ˈfəs-ˌkāt, əb-\: to make (something) more difficult to understand

Challenge: Can you create the following graph?

Rules: You may not repeat any previous answer. ## 24 thoughts on “Obfuscation Challenge #1 (Basic -> Advanced)”

1. Dan Anderson says:

First!

y = x

2. Aran W. Glancy (@aranglancy) says:

y=(x^3+x)/(x^2+1)

3. Lincoln I says:

It looks like y=x

1. admin says:

And it is! Can you come up with a different function that has the same graph?

4. mrowen says:
5. glennwaddelljr says:

y=2(1/2(x)-1/2) + 1. Not very creative, but definitely not the same as y=x.

6. Mr. H says:

x(t)=tan(2t)
y(t)=2tan(t)/(1-tan^2(t))

-pi/4<t<pi/4 (one period) but since Desmos doesn't allow pi for t I chose -.8<=t<=.8 (covers slightly more than one full period).

https://www.desmos.com/calculator/3f84ozgdvx

1. Doug says:

Would that create holes at x = (2n+1)(pi/2), for n integer?

7. Dan says:

Gauntlet thrown down! calculus, statistics, summation, PI notation, taylor series, etc.
https://www.desmos.com/calculator/r5az8lbyzm

8. Doug says:

Theta = pi/4 in polar form

9. Denis Sheeran (@MathEdisonHSNJ) says:

Obfuscated y=x, I took the graph of the normal curve, shifted it right, reduced the standard deviation, took the derivative of the curve and found the equation for the line tangent to the curve at the point below. I think it works.
https://www.desmos.com/calculator/ldp8mnypnt

10. akshay kaushik says:

No doubt it is y=x …perfect!

11. Laila says:

y=x^(x^0)

1. admin says:

Nicely done Laila!

1. Doug says:

Would that yield a removable discontinuity at (0,0)?

12. Jim says:

1. admin says: